Temporary HW: Difference between revisions

From phys813
Jump to navigationJump to search
No edit summary
Line 5: Line 5:
<math> \hat{H} = - \mu_B  \vec{\sigma} \cdot \mathbf{B} </math>
<math> \hat{H} = - \mu_B  \vec{\sigma} \cdot \mathbf{B} </math>


where <math> \mu_B is the Bohr magneton </math> and <math> \vec{\sigma}=(\hat{\sigma}_x,\hat{\sigma}_y,\hat{\sigma}_z) </math> is the vector of the Pauli matrices:
where <math> \mu_B </math> is the Bohr magneton </math> and <math> \vec{\sigma}=(\hat{\sigma}_x,\hat{\sigma}_y,\hat{\sigma}_z) </math> is the vector of the Pauli matrices:


<math> \hat{\sigma}_x =  
<math> \hat{\sigma}_x =  
Line 33: Line 33:


(c) Calculate the average energy in each of the above cases.
(c) Calculate the average energy in each of the above cases.


== Problem 2 ==
== Problem 2 ==

Revision as of 15:13, 23 February 2011

Problem 1

The Hamiltonian for an electron spin degree of freedom in the external magnetic field is given by:

where is the Bohr magneton </math> and is the vector of the Pauli matrices:

(a) In the quantum canonical ensemble, evaluate the density matrix if is along the z axis.

(b) Repeat the calculation from (a) assuming that points along the x axis.

(c) Calculate the average energy in each of the above cases.

Problem 2