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<math> G(r) = \langle s_k s_{k+r} \rangle - \langle s_k \rangle \langle s_{k+r} \rangle </math>
<math> G(r) = \langle s_k s_{k+r} \rangle - \langle s_k \rangle \langle s_{k+r} \rangle </math>


where <math> r </math> is the separation between the two spins in units of the lattice constant. The statistical average <math> \langle \ldots \rangle </math> is over all microstates. Because all lattice sites are equivalent, <math> G(r) </math> is independent of the choice of specific site <math> k </math> and depends only on the separation r (for a given temperature T and external field H). Since the average value of spin <math> \langle s_k \rangle </math> at site <math> k </math> is independent of the choice of that site (for periodic boundary conditions) and equals <math> m=M/N </math>, where <math> M </math> is magnetization, the correlation function can also be written as:
where <math> r </math> is the separation between the two spins in units of the lattice constant. The statistical average <math> \langle \ldots \rangle </math> is over all microstates. Because all lattice sites are equivalent, <math> G(r) </math> is independent of the choice of specific site <math> k </math> and depends only on the separation r (for a given temperature T and external field H). Since the average value of spin <math> \langle s_k \rangle </math> at site <math> k </math> is independent of the choice of that specific site (for periodic boundary conditions) and equals <math> m=M/N </math> (<math> M </math> is magnetization), the correlation function can also be written as:


<math> G(r) = \langle s_k s_{k+r} \rangle - m^2 </math>.
<math> G(r) = \langle s_k s_{k+r} \rangle - m^2 </math>.
   
   
The spin-spin correlation function <math> G(r) </math> is a measure of the degree to which a spin at one site is correlated with a spin at another site. If the spins are not correlated, then trivially <math> G(r) = 0 </math>. At high temperatures the interaction between spins is unimportant, and hence the spins are randomly oriented in the absence of an external magnetic field. Thus in the limit <math> k_B T \gg J </math>, we expect that <math> G(r) 0 for any r. For fixed T and H, we expect that, if spin k is up, then the two adjacent
The spin-spin correlation function <math> G(r) </math> is a measure of the degree to which a spin at one site is correlated with a spin at another site. If the spins are not correlated, then trivially <math> G(r) = 0 </math>. At high temperatures the interaction between spins is unimportant, and hence the spins are randomly oriented in the absence of an external magnetic field. Thus in the limit <math> k_B T \gg J </math>, we expect that <math> G(r) \rightarrow 0 </math> for any r. For fixed <math> T </math> and <math> H </math>, we expect that, if spin <math> k </math> is up, then the two adjacent spins will have a greater probability of being up than down. For spins further away from spin <math> k </math>, we expect that the probability that spin at site <math> k + r </math> is up or correlated will decrease. Hence, we expect that <math> G(r) \rightarrow 0 </math> as <math> r \rightarrow \infty </math>. Note that the physical meaning of the correlation is that it can be used to express magnetic susceptibility <math> \chi \propto G(r=0) = \langle m^2  
spins will have a greater probability of being up than down. For spins further away from spin k,
\rangle - \langle m \rangle^2 as one of the response functions.
we expect that the probability that spin k + r is up or correlated will decrease. Hence, we expect
that G(r) 0 as r → ∞. The magnetic susceptibility is proportional to <math> G(r=0) </math>, <math> \chi \propto G(r=0) = \langle m^2  
\rangle - \langle m \rangle^2  


(a) Consider an Ising chain of <math> N = 3 </math> spins with free boundary conditions in equilibrium with a heat  bath at temperature  
(a) Consider an Ising chain of <math> N = 3 </math> spins with free boundary conditions in equilibrium with a heat  bath at temperature  

Revision as of 15:17, 7 April 2011

Problem 1: Three Ising spins

Assume three spins are arranged in an equilateral triangle with each spin interacting with its two neighbors. The energy expression for the Ising model in an external magnetic field is give by:

(a) Find canonical partition function for this model.

(b) Find average spin .

(c) Find internal energy .

Problem 2: Spin-spin correlation function in the Ising model

We can gain further insight into the properties of the one-dimensional Ising model of ferromagnetism

by calculating the spin-spin correlation function

where is the separation between the two spins in units of the lattice constant. The statistical average is over all microstates. Because all lattice sites are equivalent, is independent of the choice of specific site and depends only on the separation r (for a given temperature T and external field H). Since the average value of spin at site is independent of the choice of that specific site (for periodic boundary conditions) and equals ( is magnetization), the correlation function can also be written as:

.

The spin-spin correlation function is a measure of the degree to which a spin at one site is correlated with a spin at another site. If the spins are not correlated, then trivially . At high temperatures the interaction between spins is unimportant, and hence the spins are randomly oriented in the absence of an external magnetic field. Thus in the limit , we expect that for any r. For fixed and , we expect that, if spin is up, then the two adjacent spins will have a greater probability of being up than down. For spins further away from spin , we expect that the probability that spin at site is up or correlated will decrease. Hence, we expect that as . Note that the physical meaning of the correlation is that it can be used to express magnetic susceptibility spins with free boundary conditions in equilibrium with a heat bath at temperature and in zero magnetic field. Enumerate all microstates and calculate and for k = 1, the first spin on the left.

Problem 3: Mean-field theory of the Heisenberg model of ferromagnetism